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Cheops TOE II by Jerry IulianoFrom the idea of the difference between the proton (NIST 1998..938.271998 Mev) and neutron (NIST 1998..939.56533 Mev):

NEUTRAL CHARGE...no spin = 939.56533 Mev= n

POSITIVE CHARGE....spin....= 938.271999231 Mev = p

n-p = q = 1.293330769 Mev

the twelfth iteration of this symbolic "spin" difference equals the "collective unconscious" constant:

q^q^q^q^q^q^q^q^q^q^q^q = 77.963543776 = C.U.

This constant is the hub of the mythological cosmic mind wheel that leads to the connection of sentient Being/Mind thought forms that bubble up as mathematical force field interactions between the four fundamental forces in the three dimensional block. That is the ratios of the four forces are:

Electromagnetic = a(em)= fine-structure constant = 1/137.03599976 (NIST 1998)

Stong force = a(s) = 14

Weak force = G(w) = Fermi coupling charge = .0000116639 Fm

Gravitational force = G(n) = 6.6728*(10^-11) mks

From the "collective unconscious" constant (C.U.) = 77.9625437724 divide the mythological number of the Egyptian primary diety ISIS (18) or ANU (18 -hydrogen) to get the dimensions of the Cheops pyramid (Churchward/Ramsey/Petrie..1887- 1910..height = 486.256 ft ; base leg = 763.81 ft):

log(C.U./ISIS(18) = ht/bl ht = 486.256009
From the "collective unconscious" constant (C.U.) the representation of the fine-structure constant [a(em)] can be derived through the trance/dream numbers of John of Patmos as the ratio of the "collective unconscious" constant: 144,37,1260,666...

[(10^(143.9999881/37))]/(10^2) = C.U.= 77.96354377

such that:

[[C.U.*(10^2)]/666]^2 = 137.036003514

The commonality of the ISIS/JOHN constant (18) reveals that the Cheops pyramid is a geometricaly symbolic representation of the fine-structure constant when used with John's trance/dream number of the beast..37*18 =666:

BETA FORM = (10^(2*ht/bl))/(.37^2) = 137.03599976

ISIS/JOHN FORM = (10^(ht/bl))*18 = C.U. = 77.96354275

ht = 486.2560047

The strong force a(s) =14 (Michio Kaku's book; QUANTUM THEORY: A Modern Introduction...page 6) can be directly related to the gravitational force G(n) through the "collective unconscious" constant (C.U.):

[[C.U./ISIS(18)]^2]*a(s) = m = Fermat form = 262.6432043..

such that the mass constituent (Plank mass...M(p) of the gravitational formula can be demonstrated as:

1/[(m^2)*37*ISIS(18)] = Planck mass =2.176674223*(10^-8) kilograms

NIST 1998--Plank mass = 2.17667*(10^-8) kilograms, where Gn) can be demonstrated as:

G(n) = h*c/2/Pi/(M(p)^2) = 6.672827599*(10^-11) mks

where h =Planck's constant = 6.62606876*(10^-34) J (NIST 1998)

where c = metric speed of light = 299792458 m (NIST 1998)

The weak force G(w).. Fermi-coupling charge =.0000116639 Fm the fourth and final field force is derived from the "collective unconscious" constant using the LEAHY/HEBREW(Sephira Malkuth number 288^2=82944 in its transformation to natural log e::

[[82944+(403/88)]^(1/Pi]/100 = 1/2.718281828 = 1/e

such that if a length of 400 divided by 403 times , producted C.U. squared divided by the stong force a(s) =14 equals the fermi coupling charge..G(w):

400/403/(C.U.^2)/a(s) = .00001166389944 = G(w)

There is a universal integer that bridges the electro/weak forces; G(w) and a(em) through the "collective unconscious" constant (C.U.):

[(sqrt25117)*11*(sqrt20)]/100 = C.U. = 77.96354276

which suggest a link to the ISIS/JOHN form through the fine-structure constant:

(666^2)/25117/(11^2)/20 = a(em) = 1/137.035999963

(Kinoshita;Cornell University 1998..1/137.035999935 =a(em)

Gravity can be derived from this integer (25117) by using the Fermat form with fine-structure:

(e^2)*(e^((2*Pi)+16))*25117*(11^2)*5/E/Pi = G(n) = 6.67282369*(10^-11)

where (e^2) = elementary charge squared = 2.566969412*(10^-38)

e= elementary charge = 1.602176461*(10^-19) C (NIST 1998)

E = electric constant = 8.8541878*(10^-12)

(e^(2*Pi))+16 uses natural log e = 2.718281828..

Interesting that the HEBREW)Sephira Malkuth..288)/CHRISTIAN/LEAHY(triple logic cube...82944)/EGYPTIAN(Cheops constructs...ht/bl) can be combined when using cosine in radians of the inverse fine-structure constant...1/a(em) =137.03599976..:

[288^(ht/bl)]/(10^2)] = COS 137.03599976 ht = 486.2560047

(10^(2*ht/bl))/(.37^2) = 137.035999931 ht = 486.2560047

These last two equations reveal the mystery of prof. Leahy's philosophy of the triple logic cube(surface area equals 82944) and the meaning behind his idea of "thinking now created 100" , a result of his analysing the tetrahedrons of the triple logic cube. The equations show a transformation of constants (.37 and 10) in the non-cosine form (linear) for fine-structure to their cosine forms. The formula

(10^(2*ht/bl))/(.37^2) = 137.03599976

reveals that the height parameter of the Cheops constructs controls the transformation to the cosine form. Subtracting one height module from the formula transforms Beta squared (.37^2) into Leahy's philosophical 100 while concurrently 10 transforms into the square root of the surface area of the triple logic cube..288:

(288^(ht/bl))/(10^2) = COS 137.035999931

The cosine action keeps the numerical value of the fine-structure constant symbolicaly equivalent. Everything involved in the transformation depends on the action in the exponent ruled by the adding or subtracting of one height of the Cheops pyramid. One height means square root of the surface area of the triple logic cube..288 divided by the"thinking now created 100" creates the ANGULAR measure in radians of the fine-structure constant. Two heights means ten divided by Beta squared (.37^2) equals the LINEAR measure of the fine-structure constant. The secret of the numerical "tools" 100,.37 and 288 is that by using these values the anglular and linear forms of the fine-structure constant become equivalent:

( 10 ^ ( 2 * ht / bl )) / ( .37 ^ 2 ) = linear

(288 ^ ( 1 * ht / bl )) / ( 10 ^ 2 ) = angular

In mathematics the only known equivalencies of angular to linear measurement is the radian or linear radius wrapped on the arc length ,180/Pi,, (straight line..180) divided by circle(Pi). Is the radian related to the fine-structure, Beta, Cheops constructs, etc.? The answer is yes because of the very definition of the radian straight line 180 (ISIS*10) brings the ISIS constant (18) into play.

Let radian = ISIS(18) * 10 / PI = 57.2957795131 = r

Then fine-structure constant can be expressed in linear inverse form:

(r^(2*ht/bl))*(37^2)/(5700^2) = a(em) = 1/137.03599996

ht = 486.25639693

in linear form:

(5700^2)/(r^(2*ht/bl))/(37^2) = 1/137.03599996

The radian form uses the Fermat constant 57 as divisor. The radian form links directly to the strong a(s)...14 and electromagnetic a(em)...1/137.03599976 forces in the Beta (.37) form through the Cheops constructs: 10^(ht/bl):

57/(r^(ht/bl) = [e^((Pi+8)/4)]/sqrt a(s) = .37/sqrt a(em)

57/(r^(ht/bl)) = 4.331313052 ht = 486.25639693

[e^((Pi+8)/4)]/sqrt a(s) = 4.331307928

.37/(sqrt a(em)) = 4.331307928

57 and 37 are used as harmonic means (1/57+1/37)...http://www.dgleahy.com/dgl/p23.html....in the fine-structure constant that is of the Fermat form; e^(Pi+8):

(sqrt 137.03599976)/(1/57+1/37) = sqrt (e^(Pi+7.999999806)

such that the strong force a(s)...14 is:

(sqrt 137.03599996)/(1/57+1/37)/(10^2*ht/bl) = a(s) = 14

ht = 486.2559686

The 57---37 harmonic determines the Planck mass M(p) in one step:

1/[[137.03599996/(1/57+1/37)^2)]*666] = M(p) = 2.176685281*(10^-8)

Substituting 2*E*h*c/(e^2) for inverse fine-structure:

((h*c)^3)*(E^2)*2*(666^2/(e^4)/Pi/((1/57+1/37)^4) = G(n) = 6.67282109*(10^-11)

which is the gravitational constant. In the interplay of the Pi and natural log e forms the following was observed:

100/[(82944+(403/88))^(1/Pi)] = e = 2.71828182..

(403+(1/333))/88*666 = 3050

[sqrt(3050*.373737..)]*180/(a(s)^2) = 31.0062766838

Pi^3 = 31.0062766803 .

.3737373 = 37/99

The radian and 57 are connected to the Cheops constructs..ht/bl

57/(r^(ht/bl)) = 10^(ht/bl)

isolate the radian:

r = [57/(10^(ht/bl))]^(bl/ht)

isolate ISIS (18):

[[(57/(10^ht/bl))]^(bl/ht)]*Pi/10 = ISIS (18)

to reduce the radian to primitive form:

(57^(bl/ht))*Pi/10 = ISIS (18)

This is the source of the beast number 666, a multiple of 37 ,through 57, and the Cheops constructs using the radian:

(57^(bl/ht))*(37*Pi)/(10^2) = 666

ht = 486.25639693

XXXXXXXXXXXXXXXXXXXX

The constructs of the Cheops pyramid contains all of the information necessary to calculate the condensation ratios of the four fundamental forces (a(em) ; a(s) ; G(w) ; G(n) ) using one measurement ratio, the Cheops constructs height = ht = 486.256 ft ....base leg = bl = 763.81 ft....Churchward/Ramsey 1910...
http://www.charm.net/~ces/trade/tback.html

The Egyptian numerical value for ISIS is 18.The number of Egyptian dieties is 37
http://www.themystica.com/mystica/articles/h/hex.html

the Theomatic number of Christ is 37 (the book THEOMATICS by Jerry Lucas chpt 3).... the albedo of the earth is .37.... the human body temperature is exactly 37 degrees C...... the covalent radius of hydrogen is 37 pm.... John of Patmos numbers 37 and 18....etc.... The ratio form ISIS 18 divided by Pi ...180/Pi....can derive all four fundamental forces of Nature through the Cheops constructs.
Source for the values of the four fundamental forces...Quantum Theory: A Modern Introduction , by Michio Kaku , page 6, (Oxford Press..1993)

e(m) = fine-structure constant = 1/137.03599976...(1998 NIST)

a(s) = strong force = 14

G(w) = weak force = fermi-coupling charge = .0000116639 Fm...(1998 NIST)

G(n) = gravitational constant = 6.6739*(10^-11) mks(Univ. of Washington 2001)

These are their numerical relationship values.

Letting Cheops height = ht = 486.256...(486.25662 or 486.2560047)

Letting Cheops base leg = bl = 763.81 (unchanged)

radian = r = ISIS 18 *10/Pi = 57.29577951

ELECTROMAGNETIC FORCE....a(em) = 1/137.03599976

(r^(ht/bl)) / 37 / 5700 = sqrt (1/*137.03599976)....ht =486.25662

STRONG FORCE.... a(s) = 14

(r^(ht/bl)) / (.37+.57) = 13.999999696......ht = 486.25662

WEAK FORCE....G(w) = .0000116639

(r^(ht/bl)) * ((1/57+1/37)^3) / 37 / 2.7 = .00001166390915...ht = 486.25662

GRAVITATIONAL FORCE ... = G(n) = 6.6739*(10^-11)

(r^(ht/bl) * ((1/57+1/37)^9) / .37^2) = 6.672887632*(10^-11)..ht=486.25662

Amazingly these same values are derived using the log form and Cheops constructs:

ELECTROMAGNETIC FORCE

(.37^2) / (10^(2*ht/bl)) = a(em) = 1/137.03599976...ht = 486.2560047

STRONG FORCE

1 / (10^(ht/bl)) / (1/57+1/37) / .37 = a(s) = 13.999999696...ht = 486.2560047

WEAK FORCE

[10^{8-(7*ht/bl)}] / c = G(w) = .000011663956...ht = 486.2560047..c=light

GRAVITATIONAL FORCE

[10^((ht/2/bl) - 8.5)] / ((30010/23/137)^(1/4)) = G(n) = 6.673925178*(10^-11)

What is the meaning of the value 30010/23/137 ? ..It is the volume of the Cheops pyramid...inverted !!!

(bl^2) * ht /3 = volumne pyramid.....ht = 486.2560002

(763.81^2) * 486.2560002 / 3 = 30010 * 23 * 137

Using the limit of vibration in the 3-dimensional fold (Planck scalar...10^-34):

[(10^(2*ht/bl)) / (10^34) / 30010 / 23 / 137)] ^ (1/4) = 6.673925178 * (10^-11)

Since the volumne of the Cheops pyramid is expressable by height and base leg then the gravitational constant G(n) using the Planck scalar and Cheops constructs in the log and volumne form can unify the electromagnetic and gravitational forces through one equality:

[(10^(2*ht/bl)) / (bl^2) / ht / (10^34) / * 3)] ^ (1/4) = G(n)

where ht = 486.2560047

where G(n) = 6.67391897 * (10^-11)(University Washington..6.67390 * (10^-11)
http://www.aip.org/enews/physnews/2000/split/pnu482-1.html

The symbolic meaning here is volumne mass representing the equivalence of the gravitational constant which affects volumne/mass = density to energies down to the Planck limit as scaled by the exact ratio of the tetrahedonal pyramidal structure (two pyramids base to base). The connection to the electromagnetic force, fine-structure constant probabilities, is through the numerator of the G(n) formula , 10^(2*ht/bl) . Substitute the denominator of the G(n) formula with Beta (.37) squared, the numerical second order phase transition constant of Nature and.....invert!!!; which results in a(em), the fine-structure constant:

(.37^2) / (10^(2*ht/bl) = a(em) = 1/137.03599976
ht=486.2560047
Beta .37 transforms the back to back pyramids into a dimensionless entity.

This produces the unification formula G(n)-----a(em); through dual Cheops tetrahedonal volumne constructs , .37/a(em) morphs from the Cheops pyramids volumne condition to a dimensionless structure:

[(.37^2)/a(em)) / (bl^2) / ht / (10^34) * 3 ] ^ (1/4) = G(n) = 6.673918978*(10^-11)
ht=486.2560047

which means the form [.37/a(em)] is gravitationaly modulo to the fourth root of Cheops pyramid volumne. What are the Beta (.37) and fine- structure constant entities? Probably the two greatest mysteries of natural science.

Beta .37:
Phase Transitions..http://webphysics.iupui.edu/251/251Sp97GFApr28.html

fine-structure constant..a(em) = 1/137.03599976..(NIST 1998)
http://www.tc.cornell.edu/er/media/1996/kinoshita.release.html
zero radius of convergence
http://www.lassp.cornell.edu/sethna/Cracks/QED.html
the 1/57+1/37 harmonic
http://www.dgleahy.com/dgl/p23.html

from the book QED by Richard Feynman...There is a most profound and beautiful question associated with the observed coupling constant e the amplitude for a real electron to emit or absorb a real photon.It is a simple number that has experimentally determined to be close to sqrta(em). My physicists friends won't recognize this number, because they like to remember it as the inverse of its square :about 137.035997... with an uncertainty of about 2 in the last decimal place. It has been a mystery ever since it was discovered more than fifty years ago and all good theoretical physicists put this number up on their wall and worry about it. Immediately you would like to know where this number for a coupling comes from: is it related to Pi or perhaps to the base of the natural log?(boy was he close here). Nobody knows. It's one of the greatest damn mysteries of physics: a magic number that comes to us with no understanding by man. You might say the " hand of God" wrote that number and "we don't know how He pushed His pencil". We know what kind of a dance to do experimentally to measure this number very accurately, but we don't know what kind of a dance to do on a computer to make this number come out---without putting it in secretly..."

J.Iuliano@aol.com




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